What is the d/(dθ)(({p}(θ))(2sin(2θ))) ?

The d/(dθ)(({p}(θ))(2sin(2θ))) is 2(d/(dθ)({p}(θ))sin(2θ)+cos(2θ)*2{p}(θ))

What is the first d/(dθ)(({p}(θ))(2sin(2θ))) ?

The first d/(dθ)(({p}(θ))(2sin(2θ))) is 2(d/(dθ)({p}(θ))sin(2θ)+cos(2θ)*2{p}(θ))

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\frac{d}{d θ} ((p (θ)) (2 sin (2 θ)))

2 (\frac{d}{d θ} (p (θ)) sin (2 θ) + cos (2 θ) \cdot 2 p (θ))

Solution steps

\frac{d}{d θ} ((p (θ)) (2 sin (2 θ)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (p (θ) sin (2 θ))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = p (θ), g = sin (2 θ)

= 2 (\frac{d}{d θ} (p (θ)) sin (2 θ) + \frac{d}{d θ} (sin (2 θ)) p (θ))

\frac{d}{d θ} (sin (2 θ)) = cos (2 θ) \cdot 2

= 2 (\frac{d}{d θ} (p (θ)) sin (2 θ) + cos (2 θ) \cdot 2 p (θ))

5 r u + 10 v r + 2 u t + 4 v t

x^{3} - (2 y - 3 z)^{3}

\frac{d ^{2}}{d x ^{2}} ((y) (x^{3}))

x^{6} y^{3} - 8 a^{3} b^{6}

[y + (4 - 2 x)]^{(2)}

What is the d/(dθ)(({p}(θ))(2sin(2θ))) ?
The d/(dθ)(({p}(θ))(2sin(2θ))) is 2(d/(dθ)({p}(θ))sin(2θ)+cos(2θ)*2{p}(θ))
What is the first d/(dθ)(({p}(θ))(2sin(2θ))) ?
The first d/(dθ)(({p}(θ))(2sin(2θ))) is 2(d/(dθ)({p}(θ))sin(2θ)+cos(2θ)*2{p}(θ))