What is factor 1/16 x^4-y^4 ?

The solution to factor 1/16 x^4-y^4 is (x/2+y)(x/2-y)((x^2)/4+y^2)

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factor 1/16 x^4-y^4

factor

\frac{1}{16} x^{4} - y^{4}

(\frac{x}{2} + y) (\frac{x}{2} - y) (\frac{x ^{2}}{4} + y^{2})

Solution steps

\frac{1}{16} x^{4} - y^{4}

Rewrite

\frac{x ^{4}}{16} - y^{4}

(\frac{1}{16} x^{2})^{2} - (y^{2})^{2}

= (\frac{1}{16} x^{2})^{2} - (y^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{1}{16} x^{2})^{2} - (y^{2})^{2} = (\frac{1}{16} x^{2} + y^{2}) (\frac{1}{16} x^{2} - y^{2})

= (\frac{1}{16} x^{2} + y^{2}) (\frac{1}{16} x^{2} - y^{2})

Factor

\frac{1}{16} x^{2} - y^{2} : \frac{1}{16} x + y \frac{1}{16} x - y

= (\frac{1}{16} x^{2} + y^{2}) \frac{1}{16} x + y \frac{1}{16} x - y

Refine

= (\frac{x}{2} + y) (\frac{x}{2} - y) (\frac{x ^{2}}{4} + y^{2})

4 h^{(3)} + 10 h^{(2)} - 8 h + 17

x (\frac{1}{2} x^{2} - 1)

co lo g_{3} (5 + lo g_{3} (5))

6 p m + 4 p n - 3 m q - 2 n q

x^{'} 2 - 36

What is factor 1/16 x^4-y^4 ?
The solution to factor 1/16 x^4-y^4 is (x/2+y)(x/2-y)((x^2)/4+y^2)