What is the d/(dt)((x)(kx(t))) ?

The d/(dt)((x)(kx(t))) is 2{x}(t) d/(dt)({x}(t))

What is the first d/(dt)((x)(kx(t))) ?

The first d/(dt)((x)(kx(t))) is 2{x}(t) d/(dt)({x}(t))

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\frac{d}{d t} ((x (t)) (k x (t)))

2 x (t) \frac{d}{d t} (x (t))

Solution steps

\frac{d}{d t} ((x (t)) (k x (t)))

Simplify

(x (t)) (k x (t)) : k x (t)^{2}

= \frac{d}{d t} (k x (t)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= k \frac{d}{d t} (x (t)^{2})

Apply the chain rule:

2 x (t) \frac{d}{d t} (x (t))

= 2 x (t) \frac{d}{d t} (x (t))

x^{2} + 19 x + 90.25

a^{3} b^{6} + 27 c^{6} d^{3}

x^{5} - 3 x

[2.1]

\frac{d}{d y} ((x) (3 x^{2}))

What is the d/(dt)((x)(kx(t))) ?
The d/(dt)((x)(kx(t))) is 2{x}(t) d/(dt)({x}(t))
What is the first d/(dt)((x)(kx(t))) ?
The first d/(dt)((x)(kx(t))) is 2{x}(t) d/(dt)({x}(t))