What is factor-z^{(2)}+4z+4 ?

The solution to factor-z^{(2)}+4z+4 is -(z-2(1+sqrt(2)))(z+2(sqrt(2)-1))

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factor-z^{(2)}+4z+4

factor

- z^{(2)} + 4 z + 4

- (z - 2 (1 + 2)) (z + 2 (2 - 1))

Solution steps

- z^{2} + 4 z + 4

Factor out common term

- 1

= - (z^{2} - 4 z - 4)

Factor

z^{2} - 4 z - 4 : (z - 2 (1 + 2)) (z - 2 (1 - 2))

= - (z - 2 (1 + 2)) (z - 2 (1 - 2))

Factor

1 - 2 : - (2 - 1)

= - (z - 2 (1 + 2)) (z - (- 2 (2 - 1)))

Apply rule

- (- a) = a

= - (z - 2 (1 + 2)) (z + 2 (2 - 1))

2 c (\frac{d ^{2} x}{d x ^{2}})

8 x^{3} + (- 65)

x 649 - 4 a 10121

5 v^{2} + (4 v + 8)

a x - b y - b x + a y

What is factor-z^{(2)}+4z+4 ?
The solution to factor-z^{(2)}+4z+4 is -(z-2(1+sqrt(2)))(z+2(sqrt(2)-1))