What are the solutions to the equation (x-2)(x-8)=0 ?

The solutions to the equation (x-2)(x-8)=0 are x=2,x=8

Find the zeros of (x-2)(x-8)=0

The zeros of (x-2)(x-8)=0 are x=2,x=8

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(x - 2) (x - 8) = 0

x = 2, x = 8

Solution steps

(x - 2) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = 2, x = 8

x^{2} - 2 x + 1 - 3 (x - 1)

∣ 8 - 3 x ∣ = \frac{9}{2}

(x - 2)^{2} - 9 = 0

- 7 \cdot 2

x^{2} + 9 < 0

What are the solutions to the equation (x-2)(x-8)=0 ?
The solutions to the equation (x-2)(x-8)=0 are x=2,x=8
Find the zeros of (x-2)(x-8)=0
The zeros of (x-2)(x-8)=0 are x=2,x=8