What is factor (4x-5)^2-7(4x-5)+12 ?

The solution to factor (4x-5)^2-7(4x-5)+12 is 4(x-2)(4x-9)

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factor (4x-5)^2-7(4x-5)+12

factor

(4 x - 5)^{2} - 7 (4 x - 5) + 12

4 (x - 2) (4 x - 9)

Solution steps

(4 x - 5)^{2} - 7 (4 x - 5) + 12

Expand

(4 x - 5)^{2} - 7 (4 x - 5) + 12 : 16 x^{2} - 68 x + 72

= 16 x^{2} - 68 x + 72

Factor

16 x^{2} - 68 x + 72 : 4 (x - 2) (4 x - 9)

= 4 (x - 2) (4 x - 9)

x \frac{1}{4} + 4

5^{x} (ln (2 y))

sin^{2} (2 x^{3} + 2 x^{2})

d x (arcsin (x))

x^{4 n} - 1 6^{2 n}

What is factor (4x-5)^2-7(4x-5)+12 ?
The solution to factor (4x-5)^2-7(4x-5)+12 is 4(x-2)(4x-9)