What are the solutions to the equation x^2+4x+11=0 ?

The solutions to the equation x^2+4x+11=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i

Find the zeros of x^2+4x+11=0

The zeros of x^2+4x+11=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i

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x^{2} + 4 x + 11 = 0

x = - 2 + 7 i, x = - 2 - 7 i

Solution steps

x^{2} + 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 11 : 27 i

x_{1, 2} = \frac{- 4 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 7 i}{2 \cdot 1}

x = \frac{- 4 + 2 7 i}{2 \cdot 1} : - 2 + 7 i

x = \frac{- 4 - 2 7 i}{2 \cdot 1} : - 2 - 7 i

The solutions to the quadratic equation are:

x = - 2 + 7 i, x = - 2 - 7 i

3 (x + 5) = 2 (3 x + 12)

3 x + 5 < 11

t (8 + t) - 3 (8 + t)

4 y = 144

4 a^{2} + 14 ab + 12 b^{2}

What are the solutions to the equation x^2+4x+11=0 ?
The solutions to the equation x^2+4x+11=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i
Find the zeros of x^2+4x+11=0
The zeros of x^2+4x+11=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i