What are the solutions to the equation x^2-(7x+6)=x+59 ?

The solutions to the equation x^2-(7x+6)=x+59 are x=13,x=-5

Find the zeros of x^2-(7x+6)=x+59

The zeros of x^2-(7x+6)=x+59 are x=13,x=-5

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x^{2} - (7 x + 6) = x + 59

x = 13, x = - 5

Solution steps

x^{2} - (7 x + 6) = x + 59

Expand

x^{2} - (7 x + 6) : x^{2} - 7 x - 6

x^{2} - 7 x - 6 = x + 59

Move

59

to the left side

x^{2} - 7 x - 65 = x

Move

x

to the left side

x^{2} - 8 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 65 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 65) = 18

x_{1, 2} = \frac{- ( - 8 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 18}{2 \cdot 1}

x = \frac{- ( - 8 ) + 18}{2 \cdot 1} : 13

x = \frac{- ( - 8 ) - 18}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 13, x = - 5

∣ x - 2 ∣ = 9

5^{\frac{3}{2}} \cdot 5^{\frac{1}{2}}

[(\frac{1}{3} + \frac{3}{8}) \div (- \frac{3}{5})] + 1

7 x^{2} + 42 x - 49

4 m + 6 = 6 m - 4

What are the solutions to the equation x^2-(7x+6)=x+59 ?
The solutions to the equation x^2-(7x+6)=x+59 are x=13,x=-5
Find the zeros of x^2-(7x+6)=x+59
The zeros of x^2-(7x+6)=x+59 are x=13,x=-5