What is factor at+az+bt+bz ?

The solution to factor at+az+bt+bz is (t+z)(a+b)

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factor at+az+bt+bz

factor

a t + a z + b t + b z

(t + z) (a + b)

Solution steps

a t + a z + b t + b z

Factor out common term

a

= a (t + z) + b t + b z

Factor out common term

b

= a (t + z) + b (t + z)

Factor out common term

(t + z)

= (t + z) (a + b)

2 x^{5} - 32

a x + 2 a y + 2 b x + 4 b y

3 a x + ab - 6 x - 2 b

[(x - 3) + y] [(x - 3) - y]

sin^{2} (0)