What are the solutions to the equation 620x-2x^2=300x+8480 ?

The solutions to the equation 620x-2x^2=300x+8480 are x=4(20-3sqrt(15)),x=4(20+3sqrt(15))

Find the zeros of 620x-2x^2=300x+8480

The zeros of 620x-2x^2=300x+8480 are x=4(20-3sqrt(15)),x=4(20+3sqrt(15))

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620 x - 2 x^{2} = 300 x + 8480

x = 4 (20 - 315), x = 4 (20 + 315)

Solution steps

620 x - 2 x^{2} = 300 x + 8480

Move

8480

to the left side

620 x - 2 x^{2} - 8480 = 300 x

Move

300 x

to the left side

- 2 x^{2} + 320 x - 8480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 320 \pm 32 0 ^{2} - 4 ( - 2 ) ( - 8480 )}{2 ( - 2 )}

32 0^{2} - 4 (- 2) (- 8480) = 4815

x_{1, 2} = \frac{- 320 \pm 48 15}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 320 + 48 15}{2 ( - 2 )}, x_{2} = \frac{- 320 - 48 15}{2 ( - 2 )}

x = \frac{- 320 + 48 15}{2 ( - 2 )} : 4 (20 - 315)

x = \frac{- 320 - 48 15}{2 ( - 2 )} : 4 (20 + 315)

The solutions to the quadratic equation are:

x = 4 (20 - 315), x = 4 (20 + 315)

2 x^{2} - 3 x = 20

\frac{( 2 )}{x} \leq x

lo g_{2} (16)

5 + \frac{1}{2}

\frac{3}{48}

What are the solutions to the equation 620x-2x^2=300x+8480 ?
The solutions to the equation 620x-2x^2=300x+8480 are x=4(20-3sqrt(15)),x=4(20+3sqrt(15))
Find the zeros of 620x-2x^2=300x+8480
The zeros of 620x-2x^2=300x+8480 are x=4(20-3sqrt(15)),x=4(20+3sqrt(15))