What is the d/(dy)(4.7^'{y}(1.1)) ?

The d/(dy)(4.7^'{y}(1.1)) is 1.1*4.7^'

What is the first d/(dy)(4.7^'{y}(1.1)) ?

The first d/(dy)(4.7^'{y}(1.1)) is 1.1*4.7^'

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\frac{d}{d y} (4. 7^{^{'}} y (1.1))

1.1 \cdot 4. 7^{'}

Solution steps

\frac{d}{d y} (4. 7^{^{'}} y (1.1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4. 7^{^{^{'}}} \cdot 1.1 \frac{d y}{d y}

Apply the common derivative:

\frac{d y}{d y} = 1

= 4. 7^{^{^{'}}} \cdot 1.1 \cdot 1

Simplify

= 1.1 \cdot 4. 7^{^{^{'}}}

12 x^{4} + (- 3) x^{2} + 0.5 x - 7

2 cos^{2} (x) - 5 cos (x) - 3

\frac{d}{d x} ((a) (e^{a x^{6}}))

3 a x + b x + 3 a y + b y

a r - 2 b r - 2 a y + 4 b y

What is the d/(dy)(4.7^'{y}(1.1)) ?
The d/(dy)(4.7^'{y}(1.1)) is 1.1*4.7^'
What is the first d/(dy)(4.7^'{y}(1.1)) ?
The first d/(dy)(4.7^'{y}(1.1)) is 1.1*4.7^'