What is factor-8y^2e^{2x}+4ye^{3x} ?

The solution to factor-8y^2e^{2x}+4ye^{3x} is 4e^{2x}y(-2y+e^x)

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factor-8y^2e^{2x}+4ye^{3x}

factor

- 8 y^{2} e^{2 x} + 4 y e^{3 x}

4 e^{2 x} y (- 2 y + e^{x})

Solution steps

- 8 y^{2} e^{2 x} + 4 y e^{3 x}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

y^{2} = yy, e^{3 x} = e^{2 x} e^{x}

= - 8 yy e^{2 x} + 4 y e^{2 x} e^{x}

Rewrite as

= - 2 \cdot 4 y e^{2 x} y + 4 y e^{2 x} e^{x}

Factor out common term

4 y e^{2 x}

= 4 y e^{2 x} (- 2 y + e^{x})

2^{x^{2} - 1}

5 (6 x^{2} + 6 x)^{'}

x^{2} + (- 3) x + 24

- 3 x^{(2)} + 64 x - 120

e^{3} x - e^{6} x

What is factor-8y^2e^{2x}+4ye^{3x} ?
The solution to factor-8y^2e^{2x}+4ye^{3x} is 4e^{2x}y(-2y+e^x)