What are the solutions to the equation 6x^2+9x+1=0 ?

The solutions to the equation 6x^2+9x+1=0 are x=(-9+sqrt(57))/(12),x=(-9-sqrt(57))/(12)

Find the zeros of 6x^2+9x+1=0

The zeros of 6x^2+9x+1=0 are x=(-9+sqrt(57))/(12),x=(-9-sqrt(57))/(12)

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6 x^{2} + 9 x + 1 = 0

x = \frac{- 9 + 57}{12}, x = \frac{- 9 - 57}{12}

Decimal Notation

x = - 0.12084 \dots, x = - 1.37915 \dots

Solution steps

6 x^{2} + 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

9^{2} - 4 \cdot 6 \cdot 1 = 57

x_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 57}{2 \cdot 6}, x_{2} = \frac{- 9 - 57}{2 \cdot 6}

x = \frac{- 9 + 57}{2 \cdot 6} : \frac{- 9 + 57}{12}

x = \frac{- 9 - 57}{2 \cdot 6} : \frac{- 9 - 57}{12}

The solutions to the quadratic equation are:

x = \frac{- 9 + 57}{12}, x = \frac{- 9 - 57}{12}

\frac{1}{2} (n - 4) - 3 = 3 - (2 n + 3)

5 \cdot 20

∣ 3 x - 2 ∣ = 7

∣ x ∣ = x + 9

2 \geq \frac{w}{2}

What are the solutions to the equation 6x^2+9x+1=0 ?
The solutions to the equation 6x^2+9x+1=0 are x=(-9+sqrt(57))/(12),x=(-9-sqrt(57))/(12)
Find the zeros of 6x^2+9x+1=0
The zeros of 6x^2+9x+1=0 are x=(-9+sqrt(57))/(12),x=(-9-sqrt(57))/(12)