What is factor b^6-6b^4+12b^2-8 ?

The solution to factor b^6-6b^4+12b^2-8 is (b+sqrt(2))^3(b-sqrt(2))^3

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factor b^6-6b^4+12b^2-8

factor

b^{6} - 6 b^{4} + 12 b^{2} - 8

(b + 2)^{3} (b - 2)^{3}

Solution steps

b^{6} - 6 b^{4} + 12 b^{2} - 8

Let

u = b^{2}

= u^{3} - 6 u^{2} + 12 u - 8

Factor

u^{3} - 6 u^{2} + 12 u - 8 : (u - 2) (u - 2) (u - 2)

= (u - 2) (u - 2) (u - 2)

Substitute back

u = b^{2}

= (b^{2} - 2) (b^{2} - 2) (b^{2} - 2)

Factor

b^{2} - 2 : (b + 2) (b - 2)

= (b + 2) (b - 2) (b^{2} - 2) (b^{2} - 2)

Factor

b^{2} - 2 : (b + 2) (b - 2)

= (b + 2) (b - 2) (b + 2) (b - 2) (b^{2} - 2)

Factor

b^{2} - 2 : (b + 2) (b - 2)

= (b + 2) (b - 2) (b + 2) (b - 2) (b + 2) (b - 2)

Refine

= (b + 2)^{3} (b - 2)^{3}

a x + b x + e x

\frac{d ^{4}}{d t ^{4}} ((y) (t^{5}))

(5 x + 1)^{3} - 1^{3}

(-) n^{3}

2 x^{2 - 6 x}

What is factor b^6-6b^4+12b^2-8 ?
The solution to factor b^6-6b^4+12b^2-8 is (b+sqrt(2))^3(b-sqrt(2))^3