What is factor 7(3n-1)^2+26(3n-1)-8 ?

The solution to factor 7(3n-1)^2+26(3n-1)-8 is 9(7n-3)(n+1)

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factor 7(3n-1)^2+26(3n-1)-8

factor

7 (3 n - 1)^{2} + 26 (3 n - 1) - 8

9 (7 n - 3) (n + 1)

Solution steps

7 (3 n - 1)^{2} + 26 (3 n - 1) - 8

Break the expression into groups

= (7 (3 n - 1)^{2} - 2 (3 n - 1)) + (28 (3 n - 1) - 8)

Factor out

(3 n - 1)

from

7 (3 n - 1)^{2} - 2 (3 n - 1) : (3 n - 1) (7 (3 n - 1) - 2)

Factor out

4

from

28 (3 n - 1) - 8 : 4 (7 (3 n - 1) - 2)

= (3 n - 1) (7 (3 n - 1) - 2) + 4 (7 (3 n - 1) - 2)

Factor out common term

7 (3 n - 1) - 2

= (7 (3 n - 1) - 2) ((3 n - 1) + 4)

Refine

= (3 n + 3) (7 (3 n - 1) - 2)

Factor

3 n + 3 : 3 (n + 1)

= 3 (7 (3 n - 1) - 2) (n + 1)

Expand

7 (3 n - 1) - 2 : 21 n - 9

= 3 (21 n - 9) (n + 1)

Factor

21 n - 9 : 3 (7 n - 3)

= 3 (7 n - 3) \cdot 3 (n + 1)

Refine

= 9 (7 n - 3) (n + 1)

2 x^{3} - 73 - 3 x + 2

3 t^{2} - 1 - 10

4 + 2 i

9 x^{2} - 30 + 25

lo g_{10} (x) (x^{5} y^{3} z)

What is factor 7(3n-1)^2+26(3n-1)-8 ?
The solution to factor 7(3n-1)^2+26(3n-1)-8 is 9(7n-3)(n+1)