What is factor-(x+3)^2+(x-1)^2 ?

The solution to factor-(x+3)^2+(x-1)^2 is -8(x+1)

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factor-(x+3)^2+(x-1)^2

factor

- (x + 3)^{2} + (x - 1)^{2}

- 8 (x + 1)

Solution steps

- (x + 3)^{2} + (x - 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x - 1)^{2} - (x + 3)^{2} = ((x - 1) + (x + 3)) ((x - 1) - (x + 3))

= ((x - 1) + (x + 3)) ((x - 1) - (x + 3))

Refine

= - 4 (2 x + 2)

Factor

- 4 (2 x + 2) : - 8 (x + 1)

= - 4 (2 x + 2)

Factor

2 x + 2 : 2 (x + 1)

= - 4 \cdot 2 (x + 1)

Multiply the numbers:

4 \cdot 2 = 8

= - 8 (x + 1)

- 6 i - 8

(x^{2}) - 8 x + 8

ClN a + H^{2} (S O^{4})

f (x) 2 (0.7)^{x}

x + 2 x - 8

What is factor-(x+3)^2+(x-1)^2 ?
The solution to factor-(x+3)^2+(x-1)^2 is -8(x+1)