What is factor p^5-(9p+p^4)+9 ?

The solution to factor p^5-(9p+p^4)+9 is (p-1)(p^2+3)(p^2-3)

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factor p^5-(9p+p^4)+9

factor

p^{5} - (9 p + p^{4}) + 9

(p - 1) (p^{2} + 3) (p^{2} - 3)

Solution steps

p^{5} - (9 p + p^{4}) + 9

- (9 p + p^{4}) = - p (p^{3} + 9)

= p^{5} - p (p^{3} + 9) + 9

Expand

p^{5} - p (p^{3} + 9) + 9 : p^{5} - p^{4} - 9 p + 9

= p^{5} - p^{4} - 9 p + 9

Factor

p^{5} - p^{4} - 9 p + 9 : (p - 1) (p^{2} + 3) (p^{2} - 3)

= (p - 1) (p^{2} + 3) (p^{2} - 3)

3 x - 6 x y - 5 z + 10 yz + y - 2 y^{2}

(5 a x y^{2} + 3 b y)^{2}

(y + 3)^{3} + 8

(z + 4)^{3} - 64

e^{2} - e (2)

What is factor p^5-(9p+p^4)+9 ?
The solution to factor p^5-(9p+p^4)+9 is (p-1)(p^2+3)(p^2-3)