What is factor 4sin^2(θ)+12sin(θ)+9 ?

The solution to factor 4sin^2(θ)+12sin(θ)+9 is (2sin(θ)+3)^2

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factor 4sin^2(θ)+12sin(θ)+9

factor

4 sin^{2} (θ) + 12 sin (θ) + 9

(2 sin (θ) + 3)^{2}

Solution steps

4 sin^{2} (θ) + 12 sin (θ) + 9

Rewrite

4 sin^{2} (θ) + 12 sin (θ) + 9

(2 sin (θ))^{2} + 2 \cdot 2 sin (θ) \cdot 3 + 3^{2}

= (2 sin (θ))^{2} + 2 \cdot 2 sin (θ) \cdot 3 + 3^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 2 sin (θ), b = 3

= (2 sin (θ) + 3)^{2}

m^{2} - n^{2} + m^{3} - n^{3}

4.294967297 \cdot 1 0^{9}

20 x^{2} + 61 + 45

1 b - 1 c + 1 d

\frac{( 4 )}{( 15 ) π}

What is factor 4sin^2(θ)+12sin(θ)+9 ?
The solution to factor 4sin^2(θ)+12sin(θ)+9 is (2sin(θ)+3)^2