What is factor 27x^6-64y^6 ?

The solution to factor 27x^6-64y^6 is (3x^2-4y^2)(9x^4+12x^2y^2+16y^4)

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factor 27x^6-64y^6

factor

27 x^{6} - 64 y^{6}

(3 x^{2} - 4 y^{2}) (9 x^{4} + 12 x^{2} y^{2} + 16 y^{4})

Solution steps

27 x^{6} - 64 y^{6}

Apply exponent rules

= (3 x^{2})^{3} - (4 y^{2})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(3 x^{2})^{3} - (4 y^{2})^{3} = (3 x^{2} - 4 y^{2}) ((3 x^{2})^{2} + 3 x^{2} \cdot 4 y^{2} + (4 y^{2})^{2})

= (3 x^{2} - 4 y^{2}) ((3 x^{2})^{2} + 3 x^{2} \cdot 4 y^{2} + (4 y^{2})^{2})

Simplify

(3 x^{2})^{2} + 3 x^{2} \cdot 4 y^{2} + (4 y^{2})^{2} : 9 x^{4} + 12 x^{2} y^{2} + 16 y^{4}

= (3 x^{2} - 4 y^{2}) (9 x^{4} + 12 x^{2} y^{2} + 16 y^{4})

x - 5 = 1

1 (- 4.94 b - 19.24) = - 4 b - 28.64

\frac{x}{2} = - 6

(- 2 x^{2})^{3}

3 x - 1 \geq 5

What is factor 27x^6-64y^6 ?
The solution to factor 27x^6-64y^6 is (3x^2-4y^2)(9x^4+12x^2y^2+16y^4)