What is factor 2ax+6xc+ba+3bc ?

The solution to factor 2ax+6xc+ba+3bc is (a+3c)(2x+b)

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factor 2ax+6xc+ba+3bc

factor

2 a x + 6 x c + ba + 3 b c

(a + 3 c) (2 x + b)

Solution steps

2 a x + 6 x c + ba + 3 b c

Rewrite as

= 2 x a + 3 \cdot 2 x c + ba + 3 b c

Factor out common term

2 x

= 2 x (a + 3 c) + ba + 3 b c

Factor out common term

b

= 2 x (a + 3 c) + b (a + 3 c)

Factor out common term

(a + 3 c)

= (a + 3 c) (2 x + b)

d e x + d e + x + 1

a^{(x + 1)}

a^{3} - 64 b^{3} c^{3}

[24]

(x^{2} + y^{2}) - 50

What is factor 2ax+6xc+ba+3bc ?
The solution to factor 2ax+6xc+ba+3bc is (a+3c)(2x+b)