What are the solutions to the equation 9x^2-(243x)/(10)+9/2 =0 ?

The solutions to the equation 9x^2-(243x)/(10)+9/2 =0 are x= 5/2 ,x= 1/5

Find the zeros of 9x^2-(243x)/(10)+9/2 =0

The zeros of 9x^2-(243x)/(10)+9/2 =0 are x= 5/2 ,x= 1/5

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9 x^{2} - \frac{243 x}{10} + \frac{9}{2} = 0

x = \frac{5}{2}, x = \frac{1}{5}

Decimal Notation

x = 2.5, x = 0.2

Solution steps

9 x^{2} - \frac{243 x}{10} + \frac{9}{2} = 0

Find Least Common Multiplier of

10, 2 : 10

Multiply by LCM=

10

9 x^{2} \cdot 10 - \frac{243 x}{10} \cdot 10 + \frac{9}{2} \cdot 10 = 0 \cdot 10

Simplify

90 x^{2} - 243 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 243 ) \pm ( - 243 ) ^{2} - 4 \cdot 90 \cdot 45}{2 \cdot 90}

(- 243)^{2} - 4 \cdot 90 \cdot 45 = 207

x_{1, 2} = \frac{- ( - 243 ) \pm 207}{2 \cdot 90}

Separate the solutions

x_{1} = \frac{- ( - 243 ) + 207}{2 \cdot 90}, x_{2} = \frac{- ( - 243 ) - 207}{2 \cdot 90}

x = \frac{- ( - 243 ) + 207}{2 \cdot 90} : \frac{5}{2}

x = \frac{- ( - 243 ) - 207}{2 \cdot 90} : \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{5}

a^{3} + a^{2}

(x - 1) (x - 2) = 0

\frac{1}{2} (2 a - 6 b + 8)

5 x - 9 = 1 - 3 x

7 - 9

What are the solutions to the equation 9x^2-(243x)/(10)+9/2 =0 ?
The solutions to the equation 9x^2-(243x)/(10)+9/2 =0 are x= 5/2 ,x= 1/5
Find the zeros of 9x^2-(243x)/(10)+9/2 =0
The zeros of 9x^2-(243x)/(10)+9/2 =0 are x= 5/2 ,x= 1/5