What is factor 243-a^5b^5 ?

The solution to factor 243-a^5b^5 is -(ab-3)(a^4b^4+3a^3b^3+9a^2b^2+27ab+81)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 243-a^5b^5

factor

243 - a^{5} b^{5}

- (ab - 3) (a^{4} b^{4} + 3 a^{3} b^{3} + 9 a^{2} b^{2} + 27 ab + 81)

Solution steps

243 - a^{5} b^{5}

Rewrite

a^{5} b^{5}

(ab)^{5}

= 243 - (ab)^{5}

Factor out common term

- 1

= - ((ab)^{5} - 243)

Factor

(ab)^{5} - 243 : (ab - 3) ((ab)^{4} + 3 (ab)^{3} + 3^{2} (ab)^{2} + 3^{3} ab + 3^{4})

= - (ab - 3) ((ab)^{4} + 3 (ab)^{3} + 3^{2} (ab)^{2} + 3^{3} ab + 3^{4})

Refine

= - (ab - 3) ((ab)^{4} + 3 (ab)^{3} + 9 (ab)^{2} + 27 ab + 81)

Simplify

- (ab - 3) ((ab)^{4} + 3 (ab)^{3} + 9 (ab)^{2} + 27 ab + 81) : - (ab - 3) (a^{4} b^{4} + 3 a^{3} b^{3} + 9 a^{2} b^{2} + 27 ab + 81)

= - (ab - 3) (a^{4} b^{4} + 3 a^{3} b^{3} + 9 a^{2} b^{2} + 27 ab + 81)

6 e^{3} f - 11 e f

(p + q)^{(n - 2)}

I n (3 q^{7})

2 - 36

- \frac{1}{3} t^{2} + 2 t + 12

What is factor 243-a^5b^5 ?
The solution to factor 243-a^5b^5 is -(ab-3)(a^4b^4+3a^3b^3+9a^2b^2+27ab+81)