What is the d/(dy)((x)(-xe^{xy})) ?

The d/(dy)((x)(-xe^{xy})) is -e^{xy}x^3

What is the first d/(dy)((x)(-xe^{xy})) ?

The first d/(dy)((x)(-xe^{xy})) is -e^{xy}x^3

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\frac{d}{d y} ((x) (- x e^{x y}))

- e^{x y} x^{3}

Solution steps

\frac{d}{d y} ((x) (- x e^{x y}))

Simplify

(x) (- x e^{x y}) : - e^{x y} x^{2}

= \frac{d}{d y} (- e^{x y} x^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x^{2} \frac{d}{d y} (e^{x y})

Apply the chain rule:

e^{x y} \frac{d}{d y} (x y)

= e^{x y} \frac{d}{d y} (x y)

\frac{d}{d y} (x y) = x

= - x^{2} e^{x y} x

Simplify

- x^{2} e^{x y} x : - e^{x y} x^{3}

= - e^{x y} x^{3}

C r + C d C l^{2}

a^{2}

3 x + 2 x ln (x)

\frac{2 x y}{x ^{2} - 2 x y}

(+ 68)^{'} + (+ 22)

What is the d/(dy)((x)(-xe^{xy})) ?
The d/(dy)((x)(-xe^{xy})) is -e^{xy}x^3
What is the first d/(dy)((x)(-xe^{xy})) ?
The first d/(dy)((x)(-xe^{xy})) is -e^{xy}x^3