What is the d/(dy)((x)(cos(xy))) ?

The d/(dy)((x)(cos(xy))) is -x^2sin(xy)

What is the first d/(dy)((x)(cos(xy))) ?

The first d/(dy)((x)(cos(xy))) is -x^2sin(xy)

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\frac{d}{d y} ((x) (cos (x y)))

- x^{2} sin (x y)

Solution steps

\frac{d}{d y} ((x) (cos (x y)))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (cos (x y))

Apply the chain rule:

- sin (x y) \frac{d}{d y} (x y)

= - sin (x y) \frac{d}{d y} (x y)

\frac{d}{d y} (x y) = x

= x (- sin (x y) x)

Simplify

x (- sin (x y) x) : - x^{2} sin (x y)

= - x^{2} sin (x y)

(sin (wt))^{2}

3 (x - y) 2 - 7 (x - y) + 2

9 - 9 i

5 y^{2} (1 - 4)

x^{'} - a x

What is the d/(dy)((x)(cos(xy))) ?
The d/(dy)((x)(cos(xy))) is -x^2sin(xy)
What is the first d/(dy)((x)(cos(xy))) ?
The first d/(dy)((x)(cos(xy))) is -x^2sin(xy)