What is factor x^2+7x-8 ?

The solution to factor x^2+7x-8 is (x-1)(x+8)

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factor x^2+7x-8

factor

x^{2} + 7 x - 8

(x - 1) (x + 8)

Solution steps

x^{2} + 7 x - 8

Break the expression into groups

= (x^{2} - x) + (8 x - 8)

Factor out

x

from

x^{2} - x : x (x - 1)

Factor out

8

from

8 x - 8 : 8 (x - 1)

= x (x - 1) + 8 (x - 1)

Factor out common term

x - 1

= (x - 1) (x + 8)

(8 i)^{3}

∣ x ∣ + 5 \leq 1

(7 - 2 x) (5 x - 2) < 0

\frac{x - 4}{6} - \frac{1}{3} < 2 (x + 1)

\frac{2 y}{5} + \frac{2}{6} = \frac{y}{2} - \frac{1}{6}