What is factor 8d^3+64e^3f^3 ?

The solution to factor 8d^3+64e^3f^3 is 8(d+2ef)(d^2-2edf+4e^2f^2)

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factor 8d^3+64e^3f^3

factor

8 d^{3} + 64 e^{3} f^{3}

8 (d + 2 e f) (d^{2} - 2 e df + 4 e^{2} f^{2})

Solution steps

8 d^{3} + 64 e^{3} f^{3}

Rewrite

8 d^{3}

(2 d)^{3}

Rewrite

64 e^{3} f^{3}

(2^{2} e f)^{3}

= (2 d)^{3} + (2^{2} e f)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 d)^{3} + (2^{2} e f)^{3} = (2 d + 2^{2} e f) ((2 d)^{2} - 2 d 2^{2} e f + (2^{2} e f)^{2})

= (2 d + 2^{2} e f) ((2 d)^{2} - 2 d 2^{2} e f + (2^{2} e f)^{2})

Simplify

(2 d + 2^{2} e f) ((2 d)^{2} - 2 d \cdot 2^{2} e f + (2^{2} e f)^{2}) : (2 d + 4 e f) (4 d^{2} - 8 e df + 16 e^{2} f^{2})

= (2 d + 4 e f) (4 d^{2} - 8 e df + 16 e^{2} f^{2})

Factor

2 d + 4 e f : 2 (d + 2 e f)

= 2 (d + 2 e f) (4 d^{2} - 8 e df + 16 e^{2} f^{2})

Factor

4 d^{2} - 8 e df + 16 e^{2} f^{2} : 4 (d^{2} - 2 e df + 4 e^{2} f^{2})

= 2 (d + 2 e f) \cdot 4 (d^{2} - 2 e df + 4 e^{2} f^{2})

Refine

= 8 (d + 2 e f) (d^{2} - 2 e df + 4 e^{2} f^{2})

\frac{3 x - 12}{x - 4}

λ [6 π^{4} γ]

x^{4} + 2^{3} - 3 x^{2}

9 x^{2} + 24 + 16

(3 (π)) - 3

What is factor 8d^3+64e^3f^3 ?
The solution to factor 8d^3+64e^3f^3 is 8(d+2ef)(d^2-2edf+4e^2f^2)