What is factor 2(x+1)^3-3(x+1)^2-6 ?

The solution to factor 2(x+1)^3-3(x+1)^2-6 is 2x^3+3x^2-7

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factor 2(x+1)^3-3(x+1)^2-6

factor

2 (x + 1)^{3} - 3 (x + 1)^{2} - 6

2 x^{3} + 3 x^{2} - 7

Solution steps

2 (x + 1)^{3} - 3 (x + 1)^{2} - 6

(x + 1)^{3} : x^{3} + 3 x^{2} + 3 x + 1

= 2 (x^{3} + 3 x^{2} + 3 x + 1) - 3 (x + 1)^{2} - 6

(x + 1)^{2} : x^{2} + 2 x + 1

= 2 (x^{3} + 3 x^{2} + 3 x + 1) - 3 (x^{2} + 2 x + 1) - 6

Expand

2 (x^{3} + 3 x^{2} + 3 x + 1) : 2 x^{3} + 6 x^{2} + 6 x + 2

= 2 x^{3} + 6 x^{2} + 6 x + 2 - 3 (x^{2} + 2 x + 1) - 6

Expand

- 3 (x^{2} + 2 x + 1) : - 3 x^{2} - 6 x - 3

= 2 x^{3} + 6 x^{2} + 6 x + 2 - 3 x^{2} - 6 x - 3 - 6

Simplify

2 x^{3} + 6 x^{2} + 6 x + 2 - 3 x^{2} - 6 x - 3 - 6 : 2 x^{3} + 3 x^{2} - 7

= 2 x^{3} + 3 x^{2} - 7

ab - 2 b + a y - 2 y

9 - 3 x

2 n^{2} - 0.7 n + 0.05

(64 x y)^{(\frac{1}{3})}

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What is factor 2(x+1)^3-3(x+1)^2-6 ?
The solution to factor 2(x+1)^3-3(x+1)^2-6 is 2x^3+3x^2-7