What is factor (4x^2-1)/(8x+16) ?

The solution to factor (4x^2-1)/(8x+16) is ((2x+1)(2x-1))/(8(x+2))

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factor (4x^2-1)/(8x+16)

factor

\frac{4 x ^{2} - 1}{8 x + 16}

\frac{( 2 x + 1 ) ( 2 x - 1 )}{8 ( x + 2 )}

Solution steps

\frac{4 x ^{2} - 1}{8 x + 16}

Factor

8 x + 16 : 8 (x + 2)

= \frac{4 x ^{2} - 1}{8 ( x + 2 )}

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= \frac{( 2 x + 1 ) ( 2 x - 1 )}{8 ( x + 2 )}

2 7^{2} + 18

a x + a y + c x + cy

c_{1} + (2 x) e^{- 3 x}

343 z^{9} - 216 x^{6} y^{3}

What is factor (4x^2-1)/(8x+16) ?
The solution to factor (4x^2-1)/(8x+16) is ((2x+1)(2x-1))/(8(x+2))