What is factor (9a^2b^4)-(3a^2b) ?

The solution to factor (9a^2b^4)-(3a^2b) is 3a^2b(3b^3-1)

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factor (9a^2b^4)-(3a^2b)

factor

(9 a^{2} b^{4}) - (3 a^{2} b)

3 a^{2} b (3 b^{3} - 1)

Solution steps

(9 a^{2} b^{4}) - (3 a^{2} b)

Remove parentheses:

(a) = a

= 9 a^{2} b^{4} - 3 a^{2} b

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

a^{2} b^{4} = a^{2} b b^{3}

= 9 a^{2} b b^{3} - 3 a^{2} b

Rewrite

9

3 \cdot 3

= 3 \cdot 3 a^{2} b b^{3} - 3 a^{2} b

Factor out common term

3 a^{2} b

= 3 a^{2} b (3 b^{3} - 1)

5 x + 5 z + c x + cz

36 x^{2} - 27 x^{2}

(2 x^{6.323}) - 7.9

x^{2} \frac{d y}{d x} - 2 x y

2 e^{5} - 2

What is factor (9a^2b^4)-(3a^2b) ?
The solution to factor (9a^2b^4)-(3a^2b) is 3a^2b(3b^3-1)