What is factor (x^3-4x^2)+(-7x+10) ?

The solution to factor (x^3-4x^2)+(-7x+10) is (x-1)(x+2)(x-5)

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factor (x^3-4x^2)+(-7x+10)

factor

(x^{3} - 4 x^{2}) + (- 7 x + 10)

(x - 1) (x + 2) (x - 5)

Solution steps

(x^{3} - 4 x^{2}) + (- 7 x + 10)

Remove parentheses:

(a) = a

= x^{3} - 4 x^{2} - 7 x + 10

Use the rational root theorem

a_{0} = 10, a_{n} = 1

The dividers of

a_{0} : 1, 2, 5, 10,

The dividers of

a_{n} : 1

Therefore, check the following rational numbers:

\pm \frac{1 , 2 , 5 , 10}{1}

\frac{1}{1}

is a root of the expression, so factor out

x - 1

= (x - 1) \frac{x ^{3} - 4 x ^{2} - 7 x + 10}{x - 1}

\frac{x ^{3} - 4 x ^{2} - 7 x + 10}{x - 1} = x^{2} - 3 x - 10

= x^{2} - 3 x - 10

Factor

x^{2} - 3 x - 10 : (x + 2) (x - 5)

= (x - 1) (x + 2) (x - 5)

(2 x - 1)^{3} + 64

2 - 3 x + 16

x^{2} d y + x y d x

(x - 4) + (2 x^{2})

x + 12 - 16

What is factor (x^3-4x^2)+(-7x+10) ?
The solution to factor (x^3-4x^2)+(-7x+10) is (x-1)(x+2)(x-5)