What is factor 4x^n+4x^{n+1}+1+x ?

The solution to factor 4x^n+4x^{n+1}+1+x is (1+x)(4x^n+1)

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factor 4x^n+4x^{n+1}+1+x

factor

4 x^{n} + 4 x^{n + 1} + 1 + x

(1 + x) (4 x^{n} + 1)

Solution steps

4 x^{n} + 4 x^{n + 1} + 1 + x

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

= 4 x^{n} + 4 x^{1} x^{n} + 1 + x

Rewrite as

= 1 \cdot 4 x^{n} + 4 x^{n} x + 1 + x

Factor out common term

4 x^{n}

= 4 x^{n} (1 + x) + 1 + x

Rewrite as

= 4 (1 + x) x^{n} + 1 \cdot (1 + x)

Factor out common term

(1 + x)

= (1 + x) (4 x^{n} + 1)

20 y 28

- \frac{15}{x ^{2} - 5 x}

w^{2 + 7 w + 12}

0.05 x^{2} - 2 x + 20

G (0.5)

What is factor 4x^n+4x^{n+1}+1+x ?
The solution to factor 4x^n+4x^{n+1}+1+x is (1+x)(4x^n+1)