What are the solutions to the equation (1-y^2)=0 ?

The solutions to the equation (1-y^2)=0 are y=1,y=-1

Find the zeros of (1-y^2)=0

The zeros of (1-y^2)=0 are y=1,y=-1

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(1 - y^{2}) = 0

y = 1, y = - 1

Solution steps

(1 - y^{2}) = 0

1 - y^{2} = 0

Move

1

to the right side

- y^{2} = - 1

Divide both sides by

- 1

y^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 1, y = - 1

1 = 1

- 1 = - 1

y = 1, y = - 1

(\frac{x ^{4}}{7 ^{- 8}})^{- 7}

2 = \frac{x + 6}{2}

x^{2} - 2 x - 4 \geq 0

- \frac{1}{2} - 3

\frac{3}{8} + \frac{1}{12}

What are the solutions to the equation (1-y^2)=0 ?
The solutions to the equation (1-y^2)=0 are y=1,y=-1
Find the zeros of (1-y^2)=0
The zeros of (1-y^2)=0 are y=1,y=-1