What is ((x^4)/(7^{-8)})^{-7} ?

The solution to ((x^4)/(7^{-8)})^{-7} is 1/(7^{56)x^{28}}

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simplify ((x^4)/(7^{-8)})^{-7}

simplify

(\frac{x ^{4}}{7 ^{- 8}})^{- 7}

\frac{1}{7 ^{56} x ^{28}}

Solution steps

(\frac{x ^{4}}{7 ^{- 8}})^{- 7}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{x ^{4}}{7 ^{- 8}})^{- 7} = \frac{1}{( \frac{x ^{4}}{7 ^{- 8}} ) ^{7}}

= \frac{1}{( \frac{x ^{4}}{7 ^{- 8}} ) ^{7}}

Simplify

(\frac{x ^{4}}{7 ^{- 8}})^{7} : 7^{56} x^{28}

= \frac{1}{7 ^{56} x ^{28}}

2 = \frac{x + 6}{2}

x^{2} - 2 x - 4 \geq 0

- \frac{1}{2} - 3

\frac{3}{8} + \frac{1}{12}

30 m^{4} n^{3} - 12 m^{3} n^{2} + 6 m^{2} n

What is ((x^4)/(7^{-8)})^{-7} ?
The solution to ((x^4)/(7^{-8)})^{-7} is 1/(7^{56)x^{28}}