What is factor x^4+y^4+(x+y)^4 ?

The solution to factor x^4+y^4+(x+y)^4 is 2(x^4+2x^3y+3x^2y^2+2xy^3+y^4)

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factor x^4+y^4+(x+y)^4

factor

x^{4} + y^{4} + (x + y)^{4}

2 (x^{4} + 2 x^{3} y + 3 x^{2} y^{2} + 2 x y^{3} + y^{4})

Solution steps

x^{4} + y^{4} + (x + y)^{4}

(x + y)^{4} : x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + y^{4}

= x^{4} + y^{4} + x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + y^{4}

Simplify

x^{4} + y^{4} + x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + y^{4} : 2 x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + 2 y^{4}

= 2 x^{4} + 4 x^{3} y + 6 x^{2} y^{2} + 4 x y^{3} + 2 y^{4}

Rewrite

4

2 \cdot 2

Rewrite

6

3 \cdot 2

= 2 x^{2 \cdot 2} + 2 \cdot 2 x^{3} y + 3 \cdot 2 x^{2} y^{2} + 2 \cdot 2 x y^{3} + 2 y^{2 \cdot 2}

Factor out common term

2

= 2 (x^{4} + 2 x^{3} y + 3 x^{2} y^{2} + 2 x y^{3} + y^{4})

x (c^{3} (ln (x)))

e (a + 4 b)^{2} - 3 (a + 4 b)

(\frac{d}{d x} (y + z (x)))^{2}

(x^{2} - 5 y^{2}) + (x - 2 y)

3 x^{2} - x^{2}

What is factor x^4+y^4+(x+y)^4 ?
The solution to factor x^4+y^4+(x+y)^4 is 2(x^4+2x^3y+3x^2y^2+2xy^3+y^4)