What is factor 2xh+2xc+4x^2+ch ?

The solution to factor 2xh+2xc+4x^2+ch is (h+2x)(2x+c)

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factor 2xh+2xc+4x^2+ch

factor

2 x h + 2 x c + 4 x^{2} + c h

(h + 2 x) (2 x + c)

Solution steps

2 x h + 2 x c + 4 x^{2} + c h

Factor

2 x h + 4 x^{2} : 2 x (h + 2 x)

Factor

2 x c + c h : c (2 x + h)

= 2 x (h + 2 x) + c (2 x + h)

Factor out common term

(h + 2 x)

= (h + 2 x) (2 x + c)

\frac{12 - 3 e}{2 e}

12 a^{2} b + 8 b y - 21 a^{2} c - 14 cy

(- 4) 3 \cdot (- 2)^{- 3}

cos^{2} (x) - 2 cos (x) - 3

(x - 2) (2 x + 1)

What is factor 2xh+2xc+4x^2+ch ?
The solution to factor 2xh+2xc+4x^2+ch is (h+2x)(2x+c)