What is the answer to roots ae^bx+c ?

The answer to roots ae^bx+c is x=-c/(ae^b);\quad a\ne 0

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roots ae^bx+c

roots

a e^{b} x + c

x = - \frac{c}{a e ^{b}}; a \neq = 0

Solution steps

a e^{b} x + c

The roots are the intercepts with the x-axis

(y = 0)

a e^{b} x + c = 0

Move

c

to the right side

a e^{b} x = - c

Divide both sides by

a e^{b}; a \neq = 0

x = - \frac{c}{a e ^{b}}; a \neq = 0

\frac{d}{d t} ((z (t)) (t^{3}))

3 (ln (3))

(ln (x)) (2 x cos (x^{2}))

(3 N) cos (14 0^{\circ})

x^{2 + 3 x + 3}

What is the answer to roots ae^bx+c ?
The answer to roots ae^bx+c is x=-c/(ae^b);\quad a\ne 0