What is the derivative of (d(cos(3x))) ?

The derivative of (d(cos(3x))) is -3dsin(3x)

What is the first derivative of (d(cos(3x))) ?

The first derivative of (d(cos(3x))) is -3dsin(3x)

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\frac{d}{d x} ((d) (cos (3 x)))

- 3 d sin (3 x)

Solution steps

\frac{d}{d x} ((d) (cos (3 x)))

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= d \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= d (- sin (3 x) \cdot 3)

Simplify

= - 3 d sin (3 x)

f (3 y)

x^{m + 2} - x^{m}

cos (2 t) (sin (4 t))^{3}

25 - 9^{2}

x^{3} x^{2} - 121

What is the derivative of (d(cos(3x))) ?
The derivative of (d(cos(3x))) is -3dsin(3x)
What is the first derivative of (d(cos(3x))) ?
The first derivative of (d(cos(3x))) is -3dsin(3x)