What is factor ye^{6x}+ye^{2x}-ye^{4x} ?

The solution to factor ye^{6x}+ye^{2x}-ye^{4x} is e^{2x}y(e^{4x}+1-e^{2x})

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factor ye^{6x}+ye^{2x}-ye^{4x}

factor

y e^{6 x} + y e^{2 x} - y e^{4 x}

e^{2 x} y (e^{4 x} + 1 - e^{2 x})

Solution steps

y e^{6 x} + y e^{2 x} - y e^{4 x}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

e^{6 x} = e^{2 x} e^{4 x}, e^{4 x} = e^{2 x} e^{2 x}

= y e^{2 x} e^{4 x} + y e^{2 x} - y e^{2 x} e^{2 x}

Factor out common term

y e^{2 x}

= y e^{2 x} (e^{4 x} + 1 - e^{2 x})

(2 x^{2}) + (x - 2)

c^{2} x + c^{2} y + 2 x + 2 y

x (x^{3} + 1) - 2 (x^{3} - 11)

\frac{64 π 2 + 128 π}{15}

a^{5} y^{5} - z^{5}

What is factor ye^{6x}+ye^{2x}-ye^{4x} ?
The solution to factor ye^{6x}+ye^{2x}-ye^{4x} is e^{2x}y(e^{4x}+1-e^{2x})