What are the solutions to the equation 0=2x^2+7x+6 ?

The solutions to the equation 0=2x^2+7x+6 are x=-3/2 ,x=-2

Find the zeros of 0=2x^2+7x+6

The zeros of 0=2x^2+7x+6 are x=-3/2 ,x=-2

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0 = 2 x^{2} + 7 x + 6

x = - \frac{3}{2}, x = - 2

Solution steps

0 = 2 x^{2} + 7 x + 6

Switch sides

2 x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 6 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 2}, x_{2} = \frac{- 7 - 1}{2 \cdot 2}

x = \frac{- 7 + 1}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 7 - 1}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 2

(4 + 8 i) (4 - 8 i)

(y^{2} - x^{5}) + (x^{5} - x^{2})

x^{2} - 46 x - 48 = 0

x^{2} = 3 x + 4

∣ 5 - 6 x ∣ = 0

What are the solutions to the equation 0=2x^2+7x+6 ?
The solutions to the equation 0=2x^2+7x+6 are x=-3/2 ,x=-2
Find the zeros of 0=2x^2+7x+6
The zeros of 0=2x^2+7x+6 are x=-3/2 ,x=-2