What is factor 2cos^2(x)+cos(x)-6 ?

The solution to factor 2cos^2(x)+cos(x)-6 is (2cos(x)-3)(cos(x)+2)

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factor 2cos^2(x)+cos(x)-6

factor

2 cos^{2} (x) + cos (x) - 6

(2 cos (x) - 3) (cos (x) + 2)

Solution steps

2 cos^{2} (x) + cos (x) - 6

Break the expression into groups

= (2 cos^{2} (x) - 3 cos (x)) + (4 cos (x) - 6)

Factor out

cos (x)

from

2 cos^{2} (x) - 3 cos (x) : cos (x) (2 cos (x) - 3)

Factor out

2

from

4 cos (x) - 6 : 2 (2 cos (x) - 3)

= cos (x) (2 cos (x) - 3) + 2 (2 cos (x) - 3)

Factor out common term

2 cos (x) - 3

= (2 cos (x) - 3) (cos (x) + 2)

4 x^{3} - x^{22}

10 x y + z + 1 + 10 x yz

\frac{3 + i}{6 + i}

216 (x - 2)^{3} - (x - 1)^{3}

75 x^{2} - 7 x - 2 + 0

What is factor 2cos^2(x)+cos(x)-6 ?
The solution to factor 2cos^2(x)+cos(x)-6 is (2cos(x)-3)(cos(x)+2)