What are the solutions to the equation x^2-3x-40=0 ?

The solutions to the equation x^2-3x-40=0 are x=8,x=-5

Find the zeros of x^2-3x-40=0

The zeros of x^2-3x-40=0 are x=8,x=-5

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x^{2} - 3 x - 40 = 0

x = 8, x = - 5

Solution steps

x^{2} - 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

x = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

x = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 8, x = - 5

\frac{( \frac{2}{5} ) ^{3} ( \frac{2}{5} ) ^{2}}{( \frac{2}{5} ) ^{4}}

- (- 10)^{2}

0.698 = 0.0003 x - 0.0138

3 x^{2} + 8 x - 3 = 0

∣ x + 3 ∣ < 4

What are the solutions to the equation x^2-3x-40=0 ?
The solutions to the equation x^2-3x-40=0 are x=8,x=-5
Find the zeros of x^2-3x-40=0
The zeros of x^2-3x-40=0 are x=8,x=-5