What is the d/(dt)((s)(6sin(2t))) ?

The d/(dt)((s)(6sin(2t))) is 12scos(2t)

What is the first d/(dt)((s)(6sin(2t))) ?

The first d/(dt)((s)(6sin(2t))) is 12scos(2t)

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\frac{d}{d t} ((s) (6 sin (2 t)))

12 s cos (2 t)

Solution steps

\frac{d}{d t} ((s) (6 sin (2 t)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \cdot 6 \frac{d}{d t} (sin (2 t))

Apply the chain rule:

cos (2 t) \frac{d}{d t} (2 t)

= cos (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= s \cdot 6 cos (2 t) \cdot 2

Simplify

= 12 s cos (2 t)

- \frac{- ( 4 ) + 66}{2}

1 + a (a - 2)

(2 x + 3) (a + b) (x - 7) (a + b)

e^{x} - e^{2 x}

π - (\frac{3 π}{5})

What is the d/(dt)((s)(6sin(2t))) ?
The d/(dt)((s)(6sin(2t))) is 12scos(2t)
What is the first d/(dt)((s)(6sin(2t))) ?
The first d/(dt)((s)(6sin(2t))) is 12scos(2t)