What is factor (8x)^{(3)}-(4y)^{(3)} ?

The solution to factor (8x)^{(3)}-(4y)^{(3)} is 64(2x-y)(4x^2+2xy+y^2)

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factor (8x)^{(3)}-(4y)^{(3)}

factor

(8 x)^{(3)} - (4 y)^{(3)}

64 (2 x - y) (4 x^{2} + 2 x y + y^{2})

Solution steps

(8 x)^{3} - (4 y)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(8 x)^{3} - (4 y)^{3} = (8 x - 4 y) ((8 x)^{2} + 8 x 4 y + (4 y)^{2})

= (8 x - 4 y) ((8 x)^{2} + 8 x 4 y + (4 y)^{2})

Simplify

(8 x - 4 y) ((8 x)^{2} + 8 x \cdot 4 y + (4 y)^{2}) : (8 x - 4 y) (64 x^{2} + 32 x y + 16 y^{2})

= (8 x - 4 y) (64 x^{2} + 32 x y + 16 y^{2})

Factor

(8 x - 4 y) (64 x^{2} + 32 x y + 16 y^{2}) : 64 (2 x - y) (4 x^{2} + 2 x y + y^{2})

= (8 x - 4 y) (64 x^{2} + 32 x y + 16 y^{2})

Factor

8 x - 4 y : 4 (2 x - y)

= 4 (2 x - y) (64 x^{2} + 32 x y + 16 y^{2})

Factor

64 x^{2} + 32 x y + 16 y^{2} : 16 (4 x^{2} + 2 x y + y^{2})

= 64 (2 x - y) (4 x^{2} + 2 x y + y^{2})

\frac{( xu )}{1 + u}

(x + 2 y^{2}) + 3 (x + 2 y) - 4

((x + 3) m \cdot x m) - 10 m

(3 x^{2} + 2) + (4 y - 2 x)

(2 - 2 i)^{\frac{1}{3}}

What is factor (8x)^{(3)}-(4y)^{(3)} ?
The solution to factor (8x)^{(3)}-(4y)^{(3)} is 64(2x-y)(4x^2+2xy+y^2)