What is factor 28x^2-4x^2-5 ?

The solution to factor 28x^2-4x^2-5 is (2sqrt(6)x+sqrt(5))(2sqrt(6)x-sqrt(5))

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factor 28x^2-4x^2-5

factor

28 x^{2} - 4 x^{2} - 5

(26 x + 5) (26 x - 5)

Solution steps

28 x^{2} - 4 x^{2} - 5

Add similar elements:

28 x^{2} - 4 x^{2} = 24 x^{2}

= 24 x^{2} - 5

Rewrite

24 x^{2} - 5

(24 x)^{2} - (5)^{2}

= (24 x)^{2} - (5)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(24 x)^{2} - (5)^{2} = (24 x + 5) (24 x - 5)

= (24 x + 5) (24 x - 5)

Refine

= (26 x + 5) (26 x - 5)

2 (a + b) 2 + 7 (a + b) - 4

lo g_{3} (arctan_{(x)} (x))

15 x + (- 11)

6 x + a x + 6 y + a y

2 (x + y)^{2} + 3 (x + y) + 1

What is factor 28x^2-4x^2-5 ?
The solution to factor 28x^2-4x^2-5 is (2sqrt(6)x+sqrt(5))(2sqrt(6)x-sqrt(5))