What is the d/(dy)((x)(2xln(x)y)) ?

The d/(dy)((x)(2xln(x)y)) is 2x^2ln(x)

What is the first d/(dy)((x)(2xln(x)y)) ?

The first d/(dy)((x)(2xln(x)y)) is 2x^2ln(x)

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\frac{d}{d y} ((x) (2 x ln (x) y))

2 x^{2} ln (x)

Solution steps

\frac{d}{d y} ((x) (2 x ln (x) y))

Simplify

(x) (2 x ln (x) y) : 2 x^{2} y ln (x)

= \frac{d}{d y} (2 x^{2} y ln (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{2} ln (x) \frac{d y}{d y}

Apply the common derivative:

\frac{d y}{d y} = 1

= 2 x^{2} ln (x) \cdot 1

Simplify

= 2 x^{2} ln (x)

10.3 [(97.987 x^{0.265}) - 1.586]

r^{8} - 4 r^{4} + 4 r^{2} - 1

\frac{25 - 5 3}{22}

ln (p x^{p - 2} - x^{p - 2} - x^{p - 1})

x^{3} + x y^{2} + a x^{2} + a y^{2}

What is the d/(dy)((x)(2xln(x)y)) ?
The d/(dy)((x)(2xln(x)y)) is 2x^2ln(x)
What is the first d/(dy)((x)(2xln(x)y)) ?
The first d/(dy)((x)(2xln(x)y)) is 2x^2ln(x)