What is the first d/(dt)((x)(+2x)) ?

The first d/(dt)((x)(+2x)) is 4t

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d/(dt)((x)(+2x))

\frac{d}{d t} ((t) (+ 2 t))

4 t

Solution steps

\frac{d}{d t} ((t) (2 t))

Simplify

(t) (2 t) : 2 t^{2}

= \frac{d}{d t} (2 t^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 t^{2 - 1}

Simplify

= 4 t

\frac{146 73 - 2}{27}

8 - 25

y (y^{'} (t))

(r cos (θ) + i r sin (θ))^{n}

\frac{d}{d x} ((t) (- t))