What is factor 3e^3+25e^2+36e-36 ?

The solution to factor 3e^3+25e^2+36e-36 is (e+3)(3e-2)(e+6)

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factor 3e^3+25e^2+36e-36

factor

3 e^{3} + 25 e^{2} + 36 e - 36

(e + 3) (3 e - 2) (e + 6)

Solution steps

3 e^{3} + 25 e^{2} + 36 e - 36

Use the rational root theorem

a_{0} = 36, a_{n} = 3

The dividers of

a_{0} : 1, 2, 3, 4, 6, 9, 12, 18, 36,

The dividers of

a_{n} : 1, 3

Therefore, check the following rational numbers:

\pm \frac{1 , 2 , 3 , 4 , 6 , 9 , 12 , 18 , 36}{1 , 3}

- \frac{3}{1}

is a root of the expression, so factor out

e + 3

= (e + 3) \frac{3 e ^{3} + 25 e ^{2} + 36 e - 36}{e + 3}

\frac{3 e ^{3} + 25 e ^{2} + 36 e - 36}{e + 3} = 3 e^{2} + 16 e - 12

= 3 e^{2} + 16 e - 12

Factor

3 e^{2} + 16 e - 12 : (3 e - 2) (e + 6)

= (e + 3) (3 e - 2) (e + 6)

3 - \frac{1}{2} x

P (x) (x - 1) (2 x^{2} + 3 x + 4)

lo g_{x} (25)

sin (180 - 3 a)

H_{2} S O_{4} + F e S O^{4}

What is factor 3e^3+25e^2+36e-36 ?
The solution to factor 3e^3+25e^2+36e-36 is (e+3)(3e-2)(e+6)