What is factor (y+z)^3-64 ?

The solution to factor (y+z)^3-64 is (y+z-4)((y+z)^2+4(y+z)+16)

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factor (y+z)^3-64

factor

(y + z)^{3} - 64

(y + z - 4) ((y + z)^{2} + 4 (y + z) + 16)

Solution steps

(y + z)^{3} - 64

Rewrite

64

4^{3}

= (y + z)^{3} - 4^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(y + z)^{3} - 4^{3} = ((y + z) - 4) ((y + z)^{2} + 4 (y + z) + 4^{2})

= ((y + z) - 4) ((y + z)^{2} + 4 (y + z) + 4^{2})

Refine

= (y + z - 4) ((y + z)^{2} + 4 (y + z) + 16)

e^{10} - 2 e

d^{2} + \frac{5}{4} d + 1

- 28 b + (- 13)

4 a^{2} - 1 a z + 4 a^{2} - z^{2}

x^{2} + y x - (6 y^{2} - 5 y + 1)

What is factor (y+z)^3-64 ?
The solution to factor (y+z)^3-64 is (y+z-4)((y+z)^2+4(y+z)+16)