What are the solutions to the equation X^2+2X-15=0 ?

The solutions to the equation X^2+2X-15=0 are X=3,X=-5

Find the zeros of X^2+2X-15=0

The zeros of X^2+2X-15=0 are X=3,X=-5

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X^{2} + 2 X - 15 = 0

X = 3, X = - 5

Solution steps

X^{2} + 2 X - 15 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

X_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 2 + 8}{2 \cdot 1}, X_{2} = \frac{- 2 - 8}{2 \cdot 1}

X = \frac{- 2 + 8}{2 \cdot 1} : 3

X = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

X = 3, X = - 5

(102)^{2}

12 x^{2} - 8 x + 1

3 x^{3} - 7 x^{2} + 3 x - 7

(x + 4) (x - 1) (x + 2) < 0

∣ 2 x + 5 ∣ < 11

What are the solutions to the equation X^2+2X-15=0 ?
The solutions to the equation X^2+2X-15=0 are X=3,X=-5
Find the zeros of X^2+2X-15=0
The zeros of X^2+2X-15=0 are X=3,X=-5