What is factor 6(b+1)^2-11(b+1)+3 ?

The solution to factor 6(b+1)^2-11(b+1)+3 is (3b+2)(2b-1)

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factor 6(b+1)^2-11(b+1)+3

factor

6 (b + 1)^{2} - 11 (b + 1) + 3

(3 b + 2) (2 b - 1)

Solution steps

6 (b + 1)^{2} - 11 (b + 1) + 3

Break the expression into groups

= (6 (b + 1)^{2} - 2 (b + 1)) + (- 9 (b + 1) + 3)

Factor out

2 (b + 1)

from

6 (b + 1)^{2} - 2 (b + 1) : 2 (b + 1) (3 (b + 1) - 1)

Factor out

- 3

from

- 9 (b + 1) + 3 : - 3 (3 (b + 1) - 1)

= 2 (b + 1) (3 (b + 1) - 1) - 3 (3 (b + 1) - 1)

Factor out common term

3 (b + 1) - 1

= (3 (b + 1) - 1) (2 (b + 1) - 3)

Expand

3 (b + 1) - 1 : 3 b + 2

= (3 b + 2) (2 (b + 1) - 3)

Expand

2 (b + 1) - 3 : 2 b - 1

= (3 b + 2) (2 b - 1)

e^{c t + d t}

e^{5} + e^{3}

16 x^{2} + (- 96) x + (141)

x^{2} + 4 + 16

- (\frac{- 9 + 69}{2})

What is factor 6(b+1)^2-11(b+1)+3 ?
The solution to factor 6(b+1)^2-11(b+1)+3 is (3b+2)(2b-1)